CVE-2024-10127
Authentication bypass condition in LDAP authentication in M-Files server versions before 24.11 supported usage of OpenLDAP configurations that allowed user authentication without a password when the LDAP server itself had the vulnerable configuration.
https://nvd.nist.gov/vuln/detail/CVE-2024-10127
Categories
CWE-303 : Incorrect Implementation of Authentication Algorithm
This incorrect implementation may allow authentication to be bypassed.
References
CPE
REMEDIATION
EXPLOITS
Exploit-db.com
id |
description |
date |
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No known exploits |
POC Github
Other Nist (github, ...)
CAPEC
Common Attack Pattern Enumerations and Classifications
id |
description |
severity |
90 |
Reflection Attack in Authentication Protocol
An adversary can abuse an authentication protocol susceptible to reflection attack in order to defeat it. Doing so allows the adversary illegitimate access to the target system, without possessing the requisite credentials. Reflection attacks are of great concern to authentication protocols that rely on a challenge-handshake or similar mechanism. An adversary can impersonate a legitimate user and can gain illegitimate access to the system by successfully mounting a reflection attack during authentication. [Identify service with vulnerable handshake authentication] The adversary must first identify a vulnerable authentication protocol. The most common indication of an authentication protocol vulnerable to reflection attack is when the client initiates the handshake, rather than the server. This allows the client to get the server to encrypt targeted data using the server's pre-shared key. [Send challenge to target server] The adversary opens a connection to the target server and sends it a challenge. This challenge is arbitrary and is simply used as a placeholder for the protocol in order to get the server to respond. [Receive server challenge] The server responds by returning the challenge sent encrypted with the server's pre-shared key, as well as its own challenge to the attacker sent in plaintext. We will call this challenge sent by the server "C". C is very important and is stored off by the adversary for the next step. [Initiate second handshake] Since the adversary does not possess the pre-shared key, they cannot encrypt C from the previous step in order for the server to authenticate them. To get around this, the adversary initiates a second connection to the server while still keeping the first connection alive. In the second connection, the adversary sends C as the initial client challenge, which rather than being arbitary like the first connection, is very intentional. [Receive encrypted challenge] The server treats the intial client challenge in connection two as an arbitrary client challenge and responds by encrypting C with the pre-shared key. The server also sends a new challenge. The adversary ignores the server challenge and stores the encrypted version of C. The second connection is either terminated or left to expire by the adversary as it is no longer needed. The adversary now posseses the encrypted version of C that is obtained through connection two. The adversary continues the handshake in connection one by responding to the server with the encrypted version of C, verifying that they have access to the pre-shared key (when they actually do not). Because the server uses the same pre-shared key for all authentication it will decrypt C and authenticate the adversary for the first connection, giving the adversary illegitimate access to the target system. |
High |
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